try_parse method Leave feedback
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Tries to parse specified raw string as a font style name.
def try_parse(cls, style, parsed):
...
| Parameter | Type | Description |
|---|---|---|
| style | str |
String that should be parsed as a font style. |
| parsed | FontStyles |
Parsed font style on success or FontStyles.Regular on failure. |
Returns: bool: True if string was successfully parsed as a correct font style; False otherwise.
- class
FontStyles
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